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mostPerformant javascript Code Snippet in 2024

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Last Updated: 1 October 2024

Returns the index of the function in an array of functions which executed the fastest.

  • Use Array.prototype.map() to generate an array where each value is the total time taken to execute the function after iterations times.
  • Use the difference in performance.now() values before and after to get the total time in milliseconds to a high degree of accuracy.
  • Use Math.min() to find the minimum execution time, and return the index of that shortest time which corresponds to the index of the most performant function.
  • Omit the second argument, iterations, to use a default of 10000 iterations.
  • The more iterations, the more reliable the result but the longer it will take.
const mostPerformant = (fns, iterations = 10000) => { const times = fns.map(fn => { const before = performance.now(); for (let i = 0; i < iterations; i++) fn(); return performance.now() - before; }); return times.indexOf(Math.min(...times)); };
mostPerformant([ () => { // Loops through the entire array before returning `false` [1, 2, 3, 4, 5, 6, 7, 8, 9, '10'].every(el => typeof el === 'number'); }, () => { // Only needs to reach index `1` before returning `false` [1, '2', 3, 4, 5, 6, 7, 8, 9, 10].every(el => typeof el === 'number'); } ]); // 1

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