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overArgs javascript Code Snippet in 2022

functionintermediate

Last Updated: 26 November 2022

Creates a function that invokes the provided function with its arguments transformed.

  • Use Array.prototype.map() to apply transforms to args in combination with the spread operator (...) to pass the transformed arguments to fn.
const overArgs = (fn, transforms) => (...args) => fn(...args.map((val, i) => transforms[i](val)));
const square = n => n * n; const double = n => n * 2; const fn = overArgs((x, y) => [x, y], [square, double]); fn(9, 3); // [81, 6]

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