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sumN javascript Code Snippet in 2022

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Last Updated: 25 September 2022

Sums all the numbers between 1 and n.

  • Use the formula (n * (n + 1)) / 2 to get the sum of all the numbers between 1 and n.
const sumN = n => (n * (n + 1)) / 2;
sumN(100); // 5050

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