n days from the given date.datetime.timedelta and the + operator to calculate the new datetime.datetime value after adding n days to d.d, to use a default value of datetime.today().from datetime import datetime, timedelta
def add_days(n, d = datetime.today()):
return d + timedelta(n)
from datetime import date add_days(5, date(2020, 10, 25)) # date(2020, 10, 30) add_days(-5, date(2020, 10, 25)) # date(2020, 10, 20)
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