enumerate()
and next()
to return the index of the last element in lst
for which fn
returns True
.def find_last_index(lst, fn): return len(lst) - 1 - next(i for i, x in enumerate(lst[::-1]) if fn(x))
find_last_index([1, 2, 3, 4], lambda n: n % 2 == 1) # 2
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