n
minimum elements from the provided list.sorted()
to sort the list.n
, to get a one-element list.n
is greater than or equal to the provided list's length, then return the original list (sorted in ascending order).def min_n(lst, n = 1): return sorted(lst, reverse = False)[:n]
min_n([1, 2, 3]) # [1] min_n([1, 2, 3], 2) # [1, 2]
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