some python Code Snippet in 2025
listintermediate
Last Updated: 17 December 2025
Checks if the provided function returns True for at least one element in the list.
- Use
any()in combination withmap()to check iffnreturnsTruefor any element in the list.
def some(lst, fn = lambda x: x):
return any(map(fn, lst))some([0, 1, 2, 0], lambda x: x >= 2 ) # True some([0, 0, 1, 0]) # True
python snippet similar to some For You in December 2025
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