some python Code Snippet in 2024
listintermediate
Last Updated: 16 December 2024
Checks if the provided function returns True for at least one element in the list.
- Use
any()in combination withmap()to check iffnreturnsTruefor any element in the list.
def some(lst, fn = lambda x: x):
return any(map(fn, lst))some([0, 1, 2, 0], lambda x: x >= 2 ) # True some([0, 0, 1, 0]) # True
python snippet similar to some For You in December 2024
Subscribe to our Newsletter
Subscribe to get resources directly to your inbox. You won't receive any spam! ✌️