True
for at least one element in the list.any()
in combination with map()
to check if fn
returns True
for any element in the list.def some(lst, fn = lambda x: x):
return any(map(fn, lst))
some([0, 1, 2, 0], lambda x: x >= 2 ) # True some([0, 0, 1, 0]) # True
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