1
and 3999
(both inclusive).for
loop to iterate over the values in lookup
.divmod()
to update num
with the remainder, adding the roman numeral representation to the result.def to_roman_numeral(num): lookup = [ (1000, 'M'), (900, 'CM'), (500, 'D'), (400, 'CD'), (100, 'C'), (90, 'XC'), (50, 'L'), (40, 'XL'), (10, 'X'), (9, 'IX'), (5, 'V'), (4, 'IV'), (1, 'I'), ] res = '' for (n, roman) in lookup: (d, num) = divmod(num, n) res += roman * d return res
to_roman_numeral(3) # 'III'
to_roman_numeral(11) # 'XI'
to_roman_numeral(1998) # 'MCMXCVIII'
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