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haveSameContents javascript Code Snippet in 2024

arrayintermediate

Last Updated: 8 June 2024

Checks if two arrays contain the same elements regardless of order.

  • Use a for...of loop over a Set created from the values of both arrays.
  • Use Array.prototype.filter() to compare the amount of occurrences of each distinct value in both arrays.
  • Return false if the counts do not match for any element, true otherwise.
const haveSameContents = (a, b) => { for (const v of new Set([...a, ...b])) if (a.filter(e => e === v).length !== b.filter(e => e === v).length) return false; return true; };
haveSameContents([1, 2, 4], [2, 4, 1]); // true

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