Set
by applying fn
to all elements in b
.Array.prototype.filter()
on a
to only keep elements, which produce values contained in b
when fn
is applied to them.const intersectionBy = (a, b, fn) => { const s = new Set(b.map(fn)); return [...new Set(a)].filter(x => s.has(fn(x))); };
intersectionBy([2.1, 1.2], [2.3, 3.4], Math.floor); // [2.1] intersectionBy( [{ title: 'Apple' }, { title: 'Orange' }], [{ title: 'Orange' }, { title: 'Melon' }], x => x.title ); // [{ title: 'Orange' }]
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