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intersectionBy javascript Code Snippet in 2024

arrayintermediate

Last Updated: 16 May 2024

Returns the elements that exist in both arrays, after applying the provided function to each array element of both.

  • Create a Set by applying fn to all elements in b.
  • Use Array.prototype.filter() on a to only keep elements, which produce values contained in b when fn is applied to them.
const intersectionBy = (a, b, fn) => { const s = new Set(b.map(fn)); return [...new Set(a)].filter(x => s.has(fn(x))); };
intersectionBy([2.1, 1.2], [2.3, 3.4], Math.floor); // [2.1] intersectionBy( [{ title: 'Apple' }, { title: 'Orange' }], [{ title: 'Orange' }, { title: 'Melon' }], x => x.title ); // [{ title: 'Orange' }]

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