dict.items()
to get a list of tuple pairs from d
and sort it using a lambda function and sorted()
.dict()
to convert the sorted list back to a dictionary.reverse
parameter in sorted()
to sort the dictionary in reverse order, based on the second argument.def sort_dict_by_value(d, reverse = False): return dict(sorted(d.items(), key = lambda x: x[1], reverse = reverse))
d = {'one': 1, 'three': 3, 'five': 5, 'two': 2, 'four': 4} sort_dict_by_value(d) # {'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5} sort_dict_by_value(d, True) # {'five': 5, 'four': 4, 'three': 3, 'two': 2, 'one': 1}
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